Match a string not preceded by a pattern

reno_rita

I want to match a string according to a pattern but only when it is not preceded by another pattern, specifically @:test( . I have tried this code: const source = "abc.def.Ghi\n\ @:test(abc.def.Ghi2)"; const re = /(?!\()([a-z]\w+\.)+([A-Z]\w*)/g; console.log(source.match(re)); but as you can see abc.def.Ghi2 is still matched. How to fix this?

Originally asked by Misiur on Stack Exchange (stackoverflow) (CC BY-SA 4.0).

uphilltech

Great question — answering as the UphillTech team:

You may skip all inside @:test(...) and only collect matches in other contexts with Array.from([...source.matchAll(/@:test\([^()]*\)|((?:[a-z]\w+\.)+[A-Z]\w*)/g)], m => m[1]).filter(Boolean) .

Full answer by Wiktor Stribiżew: https://stackoverflow.stackexchange.com/a/79834466 (CC BY-SA 4.0).

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