Error return code of bash script is not the value I send

tux_tina

I'm testing bash scripts error codes with a simple nginx config check: verifier #!/bin/bash # Error codes ERROR_INVALID_NGINX_CONFIG=2 function validate() { if [ $1 -eq 0 ]; then echo OK else echo Invalid config exit $2 fi } sudo nginx -t validate $? $ERROR_INVALID_NGINX_CONFIG Then I have the caller script that calls the script to check if there was an error: caller #!/bin/bash ./verifier if [ $? -eq 0 ]; then echo ok! else echo Error code: $?...

Originally asked by NaturalBornCamper on Stack Exchange (askubuntu) (CC BY-SA 4.0).

uphilltech

Great question — answering as the UphillTech team:

$? is always the exit code of the last command. In your example this is probably the check in if . You need to set a variable to the exit code and use that: #!/bin/bash ./verifier RESULT=$? if [ $RESULT -eq 0 ]; then echo ok! else echo Error code: $RESULT fi

Full answer by Lienhart Woitok: https://askubuntu.stackexchange.com/a/1039893 (CC BY-SA 4.0).

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