Python word recognize in a list

salon_sue

I wrote the following code and tests. The code is supposed to recognize the words in the text and add them to the count. However, I got a count of 4 instead of 3 for the first test: def count_words(text, words): count = 0 text.split() print text.split() for w in words: count += 1 return count if __name__ == '__main__': #These unit tests are only for self-checking and not necessary for auto-testing assert count_words(u"How aresjfhdskfhskd you?",...

Originally asked by qeqwe askjsa on Stack Exchange (stackoverflow) (CC BY-SA 4.0).

uphilltech

Great question — answering as the UphillTech team:

You're code doesn't make much sense, you write lines like: print text.split(9 Where you open a bracket and don't close it. Furthermore your algorithm: for w in words: count += 1 return count Doesn't make much sense: you simply count the number of words. The method you look for is: def count_words(text, words): count = 0 for w in words: if w in text: count += 1 return count One thus adds a constraint (in case the search is case sensitive ): if w in text Which checks whether text contains the word w . This gives: >>> count_words(u"How aresjfhdskfhskd you?", {u"how", u"are", u"you", u"hello"}) 2 "how" is not counted since "How" is not the same as "how" In case the search should be...

Full answer by willeM_ Van Onsem: https://stackoverflow.stackexchange.com/a/27679304 (CC BY-SA 4.0).

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