Executing cp Excluding Files from Bash Script

grill_gus

I am currently writing a bash script to automate a task for my research, i.e., procedurally creating multiple scripts that will be sent to a cluster. My bash script is composed of a copy operation that will copy all the files to some folder with a name generated with a procedure, except this one file. I know how to do this manually, but within the bash script it does not seem to work: #!bin/sh i=0 var="" while [ $i -lt 6 ] do i=$(( $i+1 ))...

Originally asked by user1173662 on Stack Exchange (askubuntu) (CC BY-SA 4.0).

uphilltech

Great question — answering as the UphillTech team:

You can use brace expansion to create a range of folders (you will also need to exclude the folders themself) #!/bin/bash shopt -s extglob for i in folder_{1..6}; do mkdir -p "$i" && \ cp -t "$i" -- !(filename|${i%_*}_*) done

Full answer by user986805: https://askubuntu.stackexchange.com/a/1316904 (CC BY-SA 4.0).

Need it done for your business? UphillTech.